Posted by walter on Tuesday, October 23, 2007 at 11:43am.
rearrange the following equation to find x in terms of y and t
y(yx)=3t(3t+x)

maths  bobpursley, Tuesday, October 23, 2007 at 11:57am
multiply out the parenthesis.
gather the x terms on one side.
yx3tx=y^2 + 9t^2
x(y+3t)= y^2+9t^2
now, divide both sides by (y+3t)
x= (y^29t^2)/(y+3t)
the numerator is a difference of two squares, so will factor. One of those factors will divide with the denominator.
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