Posted by walter on .
rearrange the following equation to find x in terms of y and t
y(yx)=3t(3t+x)

maths 
bobpursley,
multiply out the parenthesis.
gather the x terms on one side.
yx3tx=y^2 + 9t^2
x(y+3t)= y^2+9t^2
now, divide both sides by (y+3t)
x= (y^29t^2)/(y+3t)
the numerator is a difference of two squares, so will factor. One of those factors will divide with the denominator.