Posted by **walter** on Tuesday, October 23, 2007 at 11:43am.

rearrange the following equation to find x in terms of y and t

y(y-x)=3t(3t+x)

- maths -
**bobpursley**, Tuesday, October 23, 2007 at 11:57am
multiply out the parenthesis.

gather the x terms on one side.

-yx-3tx=-y^2 + 9t^2

-x(y+3t)= -y^2+9t^2

now, divide both sides by -(y+3t)

x= (y^2-9t^2)/(y+3t)

the numerator is a difference of two squares, so will factor. One of those factors will divide with the denominator.

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