Posted by shila on .
If an object is fired upward from the top of a tower at a velocity of 80 feet per second, the tower is 200 ft high, the formula is
h(t)=16t^2+80t+200, t is time h is height, how long after it is fired does the object reach the max height? It is like a quadratic equation

MAth 
tchrwill,
If an object is fired upward from the top of a tower at a velocity of 80 feet per second, the tower is 200 ft high, the formula is
h(t)=16t^2+80t+200, t is time h is height, how long after it is fired does the object reach the max height? It is like a quadratic equation
The classic equation for height reached by a body projected upward is h = Vot  gt^2/2 or Vot  16t^2 where Vo = the initial upward velocity, t = the time of flight and g = the acceleration due to gravity.
Your equation of height reached is given by h = 200 + 80t  16t^2.
The equation of motion from which you can obtain the time of flight is Vf = Vo  gt where Vf = the final velocity. Since the final final velocity is zero, we have 0 = 80  32t making t = 2.5 sec.
After 2.5 sec., it will have reached its maximum height of 200 + 80(2.5)  16(2.5)^2 = 200 + 200  100 = 300 ft. 
math 
lavonia,
i don't know