Posted by Lauren on .
An experiment called for 4.83 L of sulfur dioxide at 0 degrees C and 1.00 atm. What would be the volume of this gas at 25 degrees C and 1.00 atm?
V1= 4.83 L
V2= ?
T1= 273 K
T2= 298 K
1 atm P1 and P2
V2 = V1 * T2/T1
4.83 L * 298 K /273 K =
ANSWER: 5.27 L
Is this correct.

Chemistry 
DrBob222,
yes