I was just wondering if someone would be able to critique my answers for the following Chem questions? they range from pretty basic to a bit more...

2)which of the following is the definition of the value of Avogadro's constant:

b) the # of Carbon atoms in exactly 12g of carbon-12?

3)the mass % of Ca in milk is 0.118%. How many Ca atoms are present in 250.0g of milk?

b) 4.43*10^23 [250gmilk*0.118gCa/40.078g.molCa*6.0221*10^23?]

4)What is the mass of 7.1*10^2moles of tin(Sn)?

a)8.4*10^4g
[7.1mol*10^2 * 118.710g/mol=8.4*10^4g]

5)An element has 2 naturally occurring isotopes. The first has a mass of 78.9183u & an abundance of 50.54%, while the second has a mass of 80.9163u. The atomic mass (weighted)of the element is therefore:

b) 79.91u
[49.46*80.9163=40.0212 + 50.54%*78.9183=39.8853 = 79.91u

7)A 200.0g sample of pure MgCl2 contains:

b)2.101 formula units of MgCl2
[200gMgCl2*1mol/95.211g/mol MgCl2 =2.101 formula units

???10)How much water is present in 83.0g of Li3PO4~12H2O?

a=0.250mol, b=0.717mol, c=2.61mol, d=3.00mol...I got "D"=3.00 mol

17)WHich of the following solutions of electrolytes are expected to undergo complete ionization?
a)0.1M LiCl, c)0.1M HCl e)both a&c...I chose "E'both A&C"

I don't understand how to do the following questions:

????14)---Given the reaction:
4Zn + K2Cr2O7 + 7H2SO4 -> 2CrSO4 + K2SO4 + 7H2O

How many moles of CrSO4 are produced by allowing 9moles of Zn, 3moles of K2Cr2O7 and 14moles of H2SO4 to react?
answers:
a)1mol, b)2mol, c)3mol, d)4mol, e)5mol

????16)What volume of 0.220M HCl is required to exactly neutralize 10.0mL of 0.085M NaOH?
a)7.7mL, b)1.0mL, c)0.39mL, d)3.9mL, e)0.19mL

????25) A solution of unknown acid is made by dissolving 0.0724g of this acid in water to make a 20mL solution. This unknown acid is known to react with NaOH in a 1:1mole ratio. The solution of this acid is titrated with 17.20mL of 0.1152M NaOH to reach equivalency. What is the identity of the unknown acid????

a)HF, b)HCl, c)HBr, d)CH3COOH, e)none of the above...of course it "isn't 'd"
but how do I work this out to find out, even if it is "e"none of the above???

Thank you for your time...it's greatly appreciated!!!

2. Avogadro's constant is 6.02*10^23

3,4, and 5 are ok.
I'll check the others asap.

It would be better to put just one (perhaps two) questions per post.

7 is ok.
10 is ok.
17. Looks ok but I don't know what your other choices were. Solutions of both LiCl and HCl will be 100 ionized.

????14)---Given the reaction:

4Zn + K2Cr2O7 + 7H2SO4 -> 2CrSO4 + K2SO4 + 7H2O

How many moles of CrSO4 are produced by allowing 9moles of Zn, 3moles of K2Cr2O7 and 14moles of H2SO4 to react?
answers:
a)1mol, b)2mol, c)3mol, d)4mol, e)5mol

Just convert mols of each of the materials listed to mols CrSO4. The smallest number will be the correct answer. This is just another example ;of a limiting reagent.
9 mols Zn x (2 mols CrSO4/4 mols Zn) =xx
3 mols K2Cr2O7 x (2 mols CrSO4/1 mol K2Cr2O7) = ??
14 mols H2SO4 x (2 mols CrSO4/7 mols H2SO4) = zz


????16)What volume of 0.220M HCl is required to exactly neutralize 10.0mL of 0.085M NaOH?
a)7.7mL, b)1.0mL, c)0.39mL, d)3.9mL, e)0.19mL

HCl + NaOH ==> NaCl + H2O
mols NaOH = L x M = 0.0100 x 0.085 = ??
mols HCl must be equal to mols NaOH (from the equation it is 1:1)
Mols HCl = L x M. You have mols and M. Solve for L.


????25) A solution of unknown acid is made by dissolving 0.0724g of this acid in water to make a 20mL solution. This unknown acid is known to react with NaOH in a 1:1mole ratio. The solution of this acid is titrated with 17.20mL of 0.1152M NaOH to reach equivalency. What is the identity of the unknown acid????

mols NaOH = L x M = 0.01720 L x 0.1152 M = ??
mols NaOH = mols acid from the problem.
mols acid = grams/molar mass.
You know mols acid and grams. Solve for molar mass and that should give you a clue as to the identity of the acid. If not, calculate the molar of the compounds in each of the answers and compare. Your compound is there.


a)HF, b)HCl, c)HBr, d)CH3COOH, e)none of the above...of course it "isn't 'd"
but how do I work this out to find out, even if it is "e"none of the above???

Check my work carefully.

so for #14 I got: 4mols

#16: 1.0mL

#17...the other two choices were b-0.1MCH3COOH & then d) both A&B, that's why I didn't bother putting them in, considering b is not an electrolyte.

#25: b- HCl?

#2, about Av's #...the options were:

a)the # of Hydrogen atom in exactly 1g of hydrogen-1
b)the # of carbon atoms in exactly 12g of carbon-12
c)the # of carbon atom in exactly 1g of carbon-12
d)the # of hydrogen atoms in exactly 12g of hydrogen-12
e)the # of moles in exactly 1g of carbon-12.

thank you for your time again.

14 is ok.

16. Check you math. I get
0.01 x 0.085 = 0.00085 = mols NaOH
mols HCl = L x M
0.00085 = L x 0.220 = 0.00386 L or 3.86 mL and rounded to two places is 3.8 mL.
17 was ok and still is. You are correct that CH3COOH is a weak electrolyte.
25 is HCl. Correct.
b is correct and that is what you had. I just didn't equate it since I had the 6.02*10^23 in mind.

I made a typo above. The 3.86 rounded to two places is, of course, 3.9 mL and not 3.8 mL.

Thank you muchly!! (the questions are just from an old MT that we were to go over to study for the real MT this coming Sat.)

good luck.

thank you!

Sure, I'd be happy to help you critique your answers and explain how to solve the questions you're unsure about.

2) The correct answer is b) the number of Carbon atoms in exactly 12g of carbon-12. Avogadro's constant is defined as the number of atoms, molecules, or ions in one mole of a substance. In the case of carbon-12, one mole of carbon-12 contains exactly 6.0221 x 10^23 carbon atoms.

3) Your answer b) 4.43*10^23 is correct. To determine the number of calcium (Ca) atoms in 250.0g of milk, you must first calculate the number of moles of Ca using the given mass percentage and molar mass of Ca. Then, convert moles to the number of atoms by multiplying by Avogadro's constant.

4) Your answer a) 8.4*10^4g is correct. To find the mass of 7.1*10^2 moles of tin (Sn), you multiply the number of moles by the molar mass of tin, which is 118.710g/mol.

5) Your answer b) 79.91u is correct. To calculate the atomic mass (weighted) of the element, multiply the mass of each isotope by its abundance and sum the results.

7) Your answer b) 2.101 formula units of MgCl2 is correct. To find the number of formula units in a given mass of MgCl2, divide the mass by the molar mass of MgCl2.

10) To determine the amount of water in 83.0g of Li3PO4·12H2O, you need to calculate the number of moles of Li3PO4·12H2O using the given mass and molar mass. The coefficient in front of H2O indicates that there are 12 moles of water for every mole of Li3PO4. Multiply the number of moles of Li3PO4·12H2O by 12 to find the moles of water.

17) Your answer e) both a&c is correct. Compounds that completely ionize in solution are strong electrolytes. Both LiCl and HCl are strong electrolytes and are expected to undergo complete ionization.

14) To determine how many moles of CrSO4 are produced, you need to use the stoichiometric ratio between Zn and CrSO4. In the balanced equation, you can see that 4 moles of Zn produce 2 moles of CrSO4. Use this ratio to calculate the moles of CrSO4 produced.

16) To calculate the volume of HCl required to neutralize NaOH, you need to use the stoichiometric ratio between HCl and NaOH from the balanced equation. From the balanced equation, you can see that 1 mole of HCl reacts with 1 mole of NaOH. Use this ratio to calculate the moles of HCl, then use the molarity and volume of HCl given to determine the volume needed.

25) To determine the identity of the unknown acid, you need to use the concept of titration. The volume and concentration of NaOH used can be used to calculate the number of moles of NaOH used. Since the acid reacts with NaOH in a 1:1 mole ratio, the number of moles of the unknown acid is equal to the number of moles of NaOH used. Convert the mass of the acid to moles using its molar mass and divide by the volume to determine its molarity. Then compare this molarity with the known acids to identify the unknown acid.

I hope this helps! Let me know if you have any further questions.