Posted by **ajo** on Sunday, October 21, 2007 at 4:07pm.

In a mall, a shopper rides up an escalator between floors. at the top of the escalator, the shopper turns right and walks 9.00m to store. the magnitude of the shopper's displacement from the bottom of the escalator is 16.0m. the vertical distance between the floors is 6.00m. at what angle is the escalator inclined above the horizontal?

i just can't get the right answer for this problem, can anyone please give me some hints? THX A LOT!

- physics -
**bobpursley**, Sunday, October 21, 2007 at 4:24pm
Lets take the 9 m out of the picture.

16^2=9^2 + E^2

so solve for the Escalator length, E.

Now, having E,

E^2=6^2+ H^2 where H is the horiontal displcement. Actually, looking at the equations, there is no reason to solve for E

16^2=9^2+6^2 + H^2

solve for H.

angle= arctan 6/H

I get close to 27 degrees.

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