Posted by Marty on Saturday, October 20, 2007 at 4:56pm.
You can calculate the weight of the removed water. Change that to moles.
Next, change the grams of anhydrous sulfate salt to moles.
Compare the ratio of those two: that is the prefix x on the hydraded salt
MgSO4.xH2O
I will be happy to critique your thinking or work.
How do I change the weight of the water removed into moles?
moles water=masswater/molmass of water
where molmas is 18g/mole (you need to figure it more accurately, 2 H and one O)
Would the weight of the water removed be 3.211g - 1.570 g?
yes, of course.
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