Posted by **Drew** on Saturday, October 20, 2007 at 12:01pm.

light travells in a straight line at a constant speed of 300,000 km/sec. what is the light's acceleration?

- science-reasoning -
**anonymous**, Saturday, October 20, 2007 at 12:12pm
the key word is "constant." a=(v2-v1)/t. The final and initial velocity is equal. What does that do to the acceleration if I do not increase or decrease in speed? Plug it into the equation and let's see... a=(300,000km/sec-300,000km/sec)/time

- science-reasoning -
**Drew**, Saturday, October 20, 2007 at 12:15pm
tnx :)

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