Posted by Mary on .
a 3262 kg car starts from rest at the top of a 5m long driveway that is sloped at 20 degrees with the horizontal. If an average friction force of 612N impedes the motion, fing the speed of the car at the bottom of the driveway.
Do this with energy:
KEtop + PEtop =KEbottom+PEbottom + frictionwork
0+mgh = 1/2 m v^2 +0 + 612*5
solve for v