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December 4, 2016
Posted by **anonymous** on Friday, October 19, 2007 at 7:04pm.

- algebra1 -
**Reiny**, Friday, October 19, 2007 at 7:29pmjust translate the "English" into Math

"The length of a rectangle is twice the width" -----> L = 2w

"If the length is increased by 4 inches" -----> 2w + 4

"the width is decreased by 1 inch" ---> w+1

"perimeter is 198 inches" ----> 2(2w+4) + 2(w+1) = 198

Solve for w, let me know what you got- algebra1 -
**Reiny**, Friday, October 19, 2007 at 7:30pmtypo error, should have been

**"the width is decreased by 1 inch" ---> w-1**

"perimeter is 198 inches" ----> 2(2w+4) + 2(w-1) = 198

- algebra1 -
- algebra1 -
**anonymous**, Friday, October 19, 2007 at 7:31pmi got x= 32

- algebra1 -
**Reiny**, Friday, October 19, 2007 at 7:34pmcorrect, so the original width was 32 in and the length was 64 inches.

- algebra1 -
**anonymous**, Friday, October 19, 2007 at 7:36pmThat is how far I got on my paper, but my teacher says I need to find the new length and width as well. How would I go about doing that?

- algebra1 -
- algebra1 -
**Reiny**, Friday, October 19, 2007 at 7:46pmwell, didn't we call the new length 2w+4, put in w=32 to get 68

and didn't we call the new width w-1, put in w=32 into that to get 31

check: new perimiter = 2(68)+2(31)

=136+62

=198 !!!!- algebra1 -
**anonymous**, Friday, October 19, 2007 at 7:49pmOh,thank you so much so much for your time, i understand now!=)

- algebra1 -

- algebra1 -