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March 4, 2015

March 4, 2015

Posted by **janet** on Thursday, October 18, 2007 at 11:17pm.

a. The long run cost function

b. The short run cost function if capital is stuck at 10 units.

c. The profit maximizing level of output as a function of the price of the good, wages, rental rate on capital, the amount of capital, and some other numbers.

- microeconomics -
**economyst**, Friday, October 19, 2007 at 9:47amSince this is at least the second post of this question, I think I better answer it.

How is your calculas. Mine is a bit rusty. But here goes. (I hope there are no typos below).

Let w be the price of labor (L), z be the price of capital (K). (Let y be the lagrangian multiplier. Let 6 be the sign for partial derivitive)

TC = wL + zK

So, for any level Q, we want to:

min(wL+zK) subject to Q=K^(1/3)L^(2/3)

Set up the lagrange minimization equation:

LA = wL + zK + y(Q - f(Q,L))

first orders are:

6LA/6L = w - y(6f/6L) = 0

6LA/6K = z - y(6f/6K) = 0

6LA/6y = Q - f(Q,L) = 0

6f/6L is the marginal product of labor.

6f/6K is the marginal product of capital

Using the first two first-order equations, we get y = w/MPl = z/MPk where

MPl = (2/3)K^(1/3)L^(-1/3)

MPk = (1/3)K^(-2/3)L^(2/3)

So, MPl/MPk = w/z = 2K/L

rearrange terms to get L=2zK/w

Now then plug this L into the original production function,

Q=K^(1/3)[2zK/w]^(2/3)

solve for K (when K is optimized)

K*= [(2z/w)^(-2/3)]Q

If you do the same steps for L you get

L*= [(2z/w)^(1/3)]Q

now plug these into a total cost functions when L and K are optimized.

TC = wL* + zK*

TC = w[(2z/w)^(1/3)]Q + z[(2z/w)^(-2/3)]Q

you could collapse terms to get a single Q. But essentially, you are done. TA DA.

From here, with K fixed at 10, optimization should be a breeze.

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