Homework Help: Math

Posted by Marie on Thursday, October 18, 2007 at 5:58pm.

The length of a rectangle is 14 centimeters less than twice its width. The perimeter of the rectangle is 62cm. What are the dimensions of the rectangle?

Here is what I did:

P=2L+2W

62=2(14-W)+2W

62=28-W+2W
28-28
------------
34=-W+2W
+W +W
------------
34=3W
-- --
3 3

W=11.3

Is this right?

I don't understand how to get the length. Can you please help me?
Thanks

Math - Quidditch, Thursday, October 18, 2007 at 6:23pm
You have the right idea, but made an error early.
P=2L+2W, this is correct
L=2W-14, this is given
So, substituting...
P=2*(2W-14) + 2W
Solve this for W.
Plug the value for W back into the second equation above to find L.

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