Posted by Marie on Thursday, October 18, 2007 at 5:58pm.
The length of a rectangle is 14 centimeters less than twice its width. The perimeter of the rectangle is 62cm. What are the dimensions of the rectangle?
Here is what I did:
P=2L+2W
62=2(14W)+2W
62=28W+2W
2828

34=W+2W
+W +W

34=3W
 
3 3
W=11.3
Is this right?
I don't understand how to get the length. Can you please help me?
Thanks

Math  Quidditch, Thursday, October 18, 2007 at 6:23pm
You have the right idea, but made an error early.
P=2L+2W, this is correct
L=2W14, this is given
So, substituting...
P=2*(2W14) + 2W
Solve this for W.
Plug the value for W back into the second equation above to find L.
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