Posted by **Marie** on Thursday, October 18, 2007 at 5:58pm.

The length of a rectangle is 14 centimeters less than twice its width. The perimeter of the rectangle is 62cm. What are the dimensions of the rectangle?

Here is what I did:

P=2L+2W

62=2(14-W)+2W

62=28-W+2W

28-28

------------

34=-W+2W

+W +W

------------

34=3W

-- --

3 3

W=11.3

Is this right?

I don't understand how to get the length. Can you please help me?

Thanks

- Math -
**Quidditch**, Thursday, October 18, 2007 at 6:23pm
You have the right idea, but made an error early.

P=2L+2W, this is correct

L=2W-14, this is given

So, substituting...

P=2*(2W-14) + 2W

Solve this for W.

Plug the value for W back into the second equation above to find L.

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