Posted by **MELANA** on Thursday, October 18, 2007 at 5:14pm.

An object in equilibrium has three forces exerted on it. A 30 N force acts at 90° from the x-axis and a 44 N force acts at 60° from the x-axis. What are the magnitude and direction of the third force?

NO IDEA WHERE TO START

- IB PHYSICS -
**bobpursley**, Thursday, October 18, 2007 at 6:11pm
add these two forces, then the equilibrant is the equal and opposite force of these two.

add 30j + 44sin60 j + 44 cos60 i

check those components.

- IB PHYSICS -
**MELANA**, Thursday, October 18, 2007 at 6:53pm
i got 106.21 would that be the third force?

because i have to find the third force and the degrees(counterclockwise from the +x direction)

but i don't know what angle i am looking for, for the degrees part.

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