Posted by candance on Thursday, October 18, 2007 at 1:32am.
For the paper to go through the air perpendicular to the street and the front of the house, it should be thrown backward relative to the car, with a relative velocity of -10 mph. The forward component of motion relative to the car will be
sqrt [(20)^2 - (10)^2] = 17.3 mph
That will also be the speed relative to the ground, since the velocity component in that direction is the same relative to car or ground.
As for the angle it is thrown, relative to the car, it is cos^-1 (-10/20) or 120 degrees off the direction of motion of the car.
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