Friday

April 18, 2014

April 18, 2014

Posted by **sara** on Wednesday, October 17, 2007 at 9:49pm.

- calculus -
**drwls**, Wednesday, October 17, 2007 at 10:51pmLet y be the water level height above the vertex. The volume of water is

V = (pi/3)r^2 y

From the dimensions you have provided, r = (5/18) y

y = (18/5) r

V = (pi/3)(18/5)^2 r^3

Calculate dV/dt = (dV/dr)*(dr/dt) and evaluate it when r = 2 ft.

In your case, dr/dt = 2 ft/min

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