Posted by sara on Wednesday, October 17, 2007 at 9:49pm.
Let y be the water level height above the vertex. The volume of water is
V = (pi/3)r^2 y
From the dimensions you have provided, r = (5/18) y
y = (18/5) r
V = (pi/3)(18/5)^2 r^3
Calculate dV/dt = (dV/dr)*(dr/dt) and evaluate it when r = 2 ft.
In your case, dr/dt = 2 ft/min
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