Posted by corey on Wednesday, October 17, 2007 at 9:13pm.
H2+I2>2HI
If 3 moles of H2, I2, and HI are in a 3L flask, what will be the equilibrium amount of each. Kc=5
The answer is H2= I2= .71M, HI= 1.584M(given by teacher)
Just need to know how to do the work.

chemistry  DrBob222, Wednesday, October 17, 2007 at 9:20pm
Do you mean the problem to sound the way it does. Are these the EQUILIBRIUM concentrations? I don't think so. Otherwise, K = 1
(H2) = 3 mols/3 L = ??
(I2) = same
(HI) = same
Write the equilibrium constant expression, plug in the numbers, and solve

chemistry  DrBob222, Wednesday, October 17, 2007 at 9:36pm
I think you meant to say that 3 mols HI, H2, and I2 were placed in a 3 L container and allowed to come to equilibrium. Calculate the concentrations of each.
Write Kc = (HI)^2/(H2)(I2)
Concentrations at the beginning are 1 M for each.
At equilibrium,
(HI) = 1+2x
(H2) = 1x
(I2) = 1x
Plug into Kc expression and solve the quadratic for x, then evaluate 1x, 1x, and 1+2x.
Post your work if you get stuck.
Answer This Question
Related Questions
 chemistry  There is 0.150 moles of H2 and I2, and are brought to equilibrium in...
 Chemistry!!! PLZ PLZ HELP!!  Calculate the equilibrium amounts of each ...
 Chemistry  Consider the following equilibrium at 1000K: 2SO2 (g) + O2 (g) ¡ê ...
 chemistry  An equilibrium mixture of SO2,SO3 and O2 gases is maintained in a ...
 chem12  for the equilibrium 2HI(g) H2(g) + I2 k eq = 8.0 2.0 mol of HI are ...
 chemistry  I am given the following reaction: 2NH3(g) > N2(g) + 3H2(g) ...
 Chemistry  The following reaction has an equilibrium constant of 0.020 at a ...
 Chemistry***  A mixture containing 19.8 moles of H2 and 7.2 mole of I2 was ...
 chem12  2HI(g)H2(g) + I2(g) k eq= 8.0 2.0 mol of HI are placed in a 4.0L ...
 chem12  2HI(g)H2(g) + I2(g) k eq= 8.0 2.0 mol of HI are placed in a 4.0L ...
More Related Questions