10 people are going canoeing/tubing. some people will tube, some will canoe. tubes are $7 each. canoes are $11 each. tubes hold one person. canoes hold three. if you want to spend exactly $50, how many canoes and tubes can you buy?
what would be the equation for how many tubes and canoes you would need?
i know the equation for cost would be 7t +11c=50, but i can't figure out the other equation so I can do linear combination
Look at the post that I just helped you on below.
:-)
thank you
To find the equation for the number of tubes and canoes needed, let's start by defining the variables:
Let's say the number of tubes is represented by 't' and the number of canoes is represented by 'c'.
Since tubes hold one person each, and canoes hold three people, we can determine the total number of people participating by adding the number of people in tubes (t) to the number of people in canoes (3c).
The total number of people is given as 10, so we can set up the equation:
t + 3c = 10
This equation represents the total number of people participating in canoeing/tubing.
Now, we can go back to the equation for the cost:
7t + 11c = 50
This equation represents the cost of buying the tubes and canoes.
So, the two equations representing the number of tubes and canoes needed and the total cost are:
t + 3c = 10 (equation 1)
7t + 11c = 50 (equation 2)
Now, you can solve these two equations using the method of linear combination or any other appropriate method to determine the number of tubes and canoes that can be bought within the given constraints.