posted by jane on .
Car moving down road accelerates at uniform rate 2.8 m/s/s for 4.63 s to reach a speed of 106.7 m/s.
1) How fast was the car initially moving?
2) What distance did it travel during the a/c/c.?
This is straightforward stuff...
vf= vi + a*t solve for vi
d= vi*t + 1/2 a t^2