Nuts is dropped from a tree and falls for 8.5 seconds before it hit ground.
1) What was the displacement in meter of nut?
2) With what velocity doe nut hit ground?
3) What is the velocity of nut when it has fallen to 4.25 seconds?
4) What is displacement of nut during the time interval from 2.125 sec. to 6.375 seconds
d= 1/2 g t^2
vf=g*t
for the last, get the dispacement at the 6.3 sec, then the displacement at 2.2 sec, and subtract them.
To answer these questions, we can use the equations of motion for an object in free fall. In the case of a nut falling from a tree, we'll assume there is no air resistance.
1) Displacement:
The formula for displacement during free fall is given by:
displacement = (1/2) * acceleration * time^2
Since the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the displacement:
displacement = (1/2) * 9.8 * (8.5)^2
2) Velocity at impact:
The formula for velocity during free fall is given by:
velocity = acceleration * time
Using the same acceleration and the given time of 8.5 seconds, we can find the velocity at impact.
3) Velocity at 4.25 seconds:
We can use the same formula to find the velocity at a specific time. Given that we're looking for the velocity at 4.25 seconds, plug in the values into the equation.
4) Displacement between 2.125 sec. to 6.375 sec:
To find displacement during a specific time interval, we subtract the initial displacement from the final displacement. We can calculate the displacement at 2.125 seconds and 6.375 seconds using the formula from question 1 and then find the difference.
By plugging in the values into the appropriate equations, we can find the answers to these questions.