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Posted by on Wednesday, October 17, 2007 at 11:16am.

How do I set this up to work it?
The length of a rectangle is 1 cm longer than its width. If the diagnol of the rectangle is 4cm, what are the dimensions of the rectangle?

  • Geometry - , Wednesday, October 17, 2007 at 11:56am

    Use Pythagoras

    x^2 + (x+1)^2 = 16

    Expand to get a quadratic equation. Solve using the formula and use only the positive answer

    (I got a width of 2.28 and a length of 3.28)

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