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Train A and train B leave station going in opposite directions. Train B leaves 1/2 later than train A. Train B travels 80km/h faster than Train A. In 2 hours the trains are 3200KMs apart. How fast is each train traveling..
thank you

  • Math - ,

    Let x = speed of A and x + 80 = speed of B.

    Speed = distance/time. therefore

    Distance = speed * time

    Distance traveled by A + distance traveled by B = 3200

    This should help you solve your problem. Thanks for asking.

  • Math - ,

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    Homework Help Forum: Math
    Current Questions | Post a New Question | Answer this Question | Further Reading

    Posted by Lucas on Tuesday, October 16, 2007 at 8:47pm.

    Train A and train B leave station going in opposite directions. Train B leaves 1/2 later than train A. Train B travels 80km/h faster than Train A. In 2 hours the trains are 3200KMs apart. How fast is each train traveling..
    thank you

    The answer depends on whether the total elapsed time is 2 hours or 2.5 hours.

    The statement "In 2 hours, the trains are 3200km apart" could mean 2 hours total elapsed time including the 1/2 hour head start of train A before train B departs or 2 hours of elapsed time "after" train A traveled 1/2 hour.

    Let V = the speed of train A
    Let V + 80 = the speed of train B
    Assuming that the total travel time of both trains is 2 hours:
    1--Train A travels distance d = .5V in 1/2 hour.
    2--The travel time of train B is (3200 - .5V)/(2V + 80) = 1.5 hours
    3--3200 - .5V = 3V + 120
    4--3.5V = 3080 making V = 880 km/hr.
    5--Train B's speed is therefore 960km/hr.
    Check:
    Train A travels 440km in the first 1/2 hour.
    This results in 2760km between the two trains when train B departs.
    They are seperating from one another at the combined speed of 880 + 960 = 1840KM/HR.
    The time required for them to be 3200km apart at the end of 2 hours is t = 2760/1840 = 1.5 hours.
    Total elapsed time is 1/2 + 1.5 = 2 hours.

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