Saturday

October 25, 2014

October 25, 2014

Posted by **STEPH** on Tuesday, October 16, 2007 at 2:18pm.

(a) Find the maximum height of the ball above the ground.

(b) Calculate the speed of the ball at the highest point in the trajectory.

- PHYSICS -
**bobpursley**, Tuesday, October 16, 2007 at 2:43pmBreak the velocty into vertical and horizontal components.

Then, height=1.2 + vivertical*t-4.9t^2

and hmax occurs at the t when

Vv=0=vivertical -9.8t

**Answer this Question**

**Related Questions**

Physics - A ball is thrown from a point 1.0 m above the ground. The initial ...

physics - A ball is thrown from a point 1.38 m above the ground. The initial ...

Physics - A ball is thrown from a point 1.38 m above the ground. The initial ...

Physics - A ball is thrown from a point 1.38 m above the ground. The initial ...

Physics - A ball is thrown from a point 1.38 m above the ground. The initial ...

Physics - A ball is thrown from a point 1.1 m above the ground. The initial ...

PHYSICS - A ball is thrown from a point 1.1 m above the ground. The initial ...

PHYSICS - A ball is thrown from a point 1.1 m above the ground. The initial ...

Physics - A ball is thrown towards a vertical wall from a point 2m above the ...

Physics - A 0.2 kg baseball located at the top of a building which is 100 m ...