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AP lost

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An elevator and its load have a combined mass of 1550 kg. Find the tension in the supporting cable in Newtons when the elevator , originally moving downward at 11 m/s, is brought to rest with constant acceleration in a distance of 43 m.

  • AP lost -

    Tension= mg +- ma where a is the acceleration. + when the elevator is going up (it adds to tension), and - going down, it reduces tension when falling.

    a= change velocity/time (rest means zero velocity)

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