Will check my work and help me with the last two problems please?

A 4 kg ball has a momentum of 12 kg m/s. What is the ball's speed?
-(12 kg/m/s) / 4kg=3m/s

A ball is moving at 4 m/s and has a momentum of 48 kg m/s. What is the ball's mass?
-(48kg/m/s) / (4m/s) =12 kg

A 1-kg chunk of putty moving at 1 m/s collides with and sticks to a 5-kg bowling ball initially at rest. The bowling ball and putty then move with a momentum of? (This one I don't know how to work)

A 1000-kg car moving at 10 m/s brakes to a stop in 5 s. The average braking force is? (This one I don't know how to work)

on the fourth: comentum is conserved, final momentum is = initial momentum.

on the last:
vf^2=vi^2+force*distance

where distance is average velocity*time or
(vf+vi)/2 * t

solve for force

first two correct.

Sure! Let's work through the last two problems together.

For the problem involving the collision between the putty and the bowling ball, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

Before the collision, the putty has a momentum of 1 kg * 1 m/s = 1 kg m/s, and the bowling ball has a momentum of 0 kg m/s since it is initially at rest. The total momentum before the collision is therefore 1 kg m/s + 0 kg m/s = 1 kg m/s.

After the collision, the putty and the bowling ball stick together and move with a common velocity. Let's assume the final velocity of the combined system is v m/s.

According to the principle of conservation of momentum, the total momentum after the collision is still 1 kg m/s, which is equal to the mass of the combined system (1 kg + 5 kg = 6 kg) multiplied by the common velocity v.

Therefore, we have the equation: 6 kg * v = 1 kg m/s.

To find the velocity v, we can divide both sides of the equation by 6 kg: v = 1 kg m/s / 6 kg = 1/6 m/s.

So, the bowling ball and putty move with a momentum of 1 kg m/s, and their common velocity is 1/6 m/s.

For the next problem involving the car braking to a stop, we can use the concept of average acceleration to find the average braking force. The average acceleration is the change in velocity divided by the time taken. In this case, the change in velocity is from 10 m/s to 0 m/s, and the time taken is 5 s.

Using the equation for average acceleration: average acceleration = change in velocity / time taken, we have: average acceleration = (0 m/s - 10 m/s) / 5 s = -10 m/s^2 (negative sign indicates deceleration).

The average braking force can be determined using Newton's second law of motion, which states that force is equal to mass multiplied by acceleration: force = mass * acceleration.

In this case, the mass of the car is given as 1000 kg. Plugging in the values, we have: average braking force = 1000 kg * (-10 m/s^2) = -10,000 N (negative sign indicates opposing direction of force compared to motion).

Therefore, the average braking force experienced by the car is -10,000 N.

I hope this helps! Let me know if you have any further questions.