Posted by **Lindsay** on Monday, October 15, 2007 at 6:24pm.

A stone is thrown vertically upward. On its way up it passes point A with speed v, and point B, 12.6 m higher than A, with speed v/2. Calculate the maximum height reached by the stone above point B.

I am still stuck on this problem, mainly because I can't seem to get v/2. I think I know all the steps...but not having v/2 is keeping me from doing them.

## Answer This Question

## Related Questions

- physics - A stone is thrown vertically upward. On its way up it passes point A ...
- Physics 4a - A stone is thrown vertically upward. On its way up it passes point ...
- physics - A stone is thrown vertically upward. On its way up it passes point A ...
- Physics - A stone is thrown vertically upward. On its way up it passes point A ...
- Physics - A stone is thrown vertically upward. On its way up it passes point A ...
- physics - A stone is thrown vertically upward. On its way up it passes point A ...
- PSU - A 2.3kg stone is thrown from ground directly upward. the maximum height ...
- physics - A stone with mass m = 2.3 kg is thrown vertically upward into the air ...
- physics - A ball is thrown vertically upward with an initial speed of 20 m/s. ...
- Physics - A stone is thrown vertically upward at an initial speed of 10m/s. Find...

More Related Questions