Posted by John on Monday, October 15, 2007 at 5:56pm.
Two more Algebra questions :
Drawing a blank on this one, not sure where to start.
Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x + 3y = 12 and passing through (9, -5).
I have half a solution to this one:
Solve the system of equations using the substitution method.
If the answer is a unique solution, present it as an ordered pair: (x, y). If not, specify whether the answer is “no solution” or “infinitely many solutions.”
4x + y = 4
2x + 8y = 0
First I did
4x - 4x + y = 4 - 4x
y = 4 - 4x
2x + 8(4-4x) = 0
2x + 32 - 32x = 0
2x + 32 - 32x = 0-32
2x - 32x = -32
-30x = -32
-30x/30 = -32/30
x = 32/30
x = 16/15
y = 4 - 4x
y = 4 - 4(16/15)
This is where I am stuck...
So i got x = 16/15 an y = ?
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