Calculus
posted by Suzy on .
22. Divide the expression before differentiating.
F(x) = (8x^3  1)/ (2x  1)
Would the way to solve this problem be...
F(x) = [(8x^3) / (2x  1)]  [(1)/(2x  1)]
= [(4x^2)/(1)]  [(1) / (2x  1)]
= (4x^2)  (2x1)^1
F'(x) = (8x + 1)

No.
The numerator is a difference of two squares, factor it, then, the denominator divides out evenly. Your answer is wrong.