Tuesday

November 25, 2014

November 25, 2014

Posted by **Anonymous** on Sunday, October 14, 2007 at 11:16am.

Work:

(10kg)(9.8m/s^2)(sin40)-T=10a

a=4.20m/s^2

T=5a

T=21N

However, the answer is 4.43m/s^2 and 204N.

- physics -
**bobpursley**, Sunday, October 14, 2007 at 4:06pmNo.

The pulling force is 5*anglefunction*g

the angle function is either sin or cosine, I dont know how the 40 deg was measured. If it was measured from the vertical, then it is Cosine.

Then

Pulling force = total mass *a

where total mass is 15kg

- physics -
**Anonymous**, Wednesday, November 7, 2012 at 8:43am, or

Then, Equation (1) yields

**Answer this Question**

**Related Questions**

physics - Two packing crate of masses 10.0kg and 5.00kg are connected by a ...

Physics - Two objects are connected by a light string that passes over a ...

Physics - Two objects are connected by a light string that passes over a ...

Physics - Two packing crates of masses m1 = 10.0 kg and m2 = 3.20 kg are ...

Physics - Two packing crates of masses m1 = 10.0 kg and m2 = 6.60 kg are ...

Physics - Two packing crates of masses 7.57 kg and 4.51 kg are connected by a ...

Physics - Two packing crates of masses m1 = 10.0 kg and m2 = 6.50 kg are ...

Physics - Two packing crates of masses m1 = 10.0 kg and m2 = 3.50 kg are ...

physics - Two packing crates of masses 7.88 kg and 4.62 kg are connected by a ...

Physics - Two packing crates of masses m1 = 10.0 kg and m2 = 4.10 kg are ...