Posted by maggie r on Sunday, October 14, 2007 at 9:22am.
Your information is contradictory. First, you say, "One parent is heterozygous and one is homozygous dominant for a gene that causes DIDS." This leads me to think that SIDS is dominant.
Later you say, "To have this disease, the child has to be homozygous recessive (ss).", which indicates that it is recessive. Which is it?
Assuming that it is recessive — one parent has SS and the other has Ss, half of the children will have Ss, but none will have SIDS. If either from this half marries an Ss, there will be a 1/4 probability of having an ss with SIDS. The probability of both/all events occurring is found by multiplying the probability of the individual events.
I hope this helps. If not, repost with a clearer definition of the problem. Thanks for asking.
well one parent is heterozygous (Ss) and the other is homozygous dominant (SS)They will have children: SS Ss SS and Ss.What are the chances of those children having children with SIDS with a parent who is heterozygous (Ss)? Does that help because I got .625% even through I dont really understand the problem.
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