Saturday

August 30, 2014

August 30, 2014

Posted by **Ashley** on Saturday, October 13, 2007 at 11:52pm.

8.Write an equation in standard form of the parabola that has the same shape as the graph of f(x) = 11x^2, but which has its vertex at (2, 9).

10. Use the vertex and intercepts to sketch the graph of the quadratic function.

y + 3 = (x + 6)^2

- algebra II -
**Reiny**, Sunday, October 14, 2007 at 1:19am8.

Clearly it must be y-9 = 11(x-2)^2

10.

sketch y = x^2, then move it 6 units to the left and 3 units up

- algebra II -
**april**, Monday, October 22, 2007 at 10:57pm5x-y=3

y=5x-3

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