Friday

April 18, 2014

April 18, 2014

Posted by **Ashley** on Saturday, October 13, 2007 at 11:52pm.

8.Write an equation in standard form of the parabola that has the same shape as the graph of f(x) = 11x^2, but which has its vertex at (2, 9).

10. Use the vertex and intercepts to sketch the graph of the quadratic function.

y + 3 = (x + 6)^2

- algebra II -
**Reiny**, Sunday, October 14, 2007 at 1:19am8.

Clearly it must be y-9 = 11(x-2)^2

10.

sketch y = x^2, then move it 6 units to the left and 3 units up

- algebra II -
**april**, Monday, October 22, 2007 at 10:57pm5x-y=3

y=5x-3

**Related Questions**

Math - write an equation in standard form of the parabola that has the same ...

Alg II/Trig - A parabola has a vertex at (0,0); a horizontal axis; and the point...

algebra - 1)What is the distance between the museum and sailing club.I cant post...

Algebra 1 parabola's - I have a graph with a parabola on it and asked to write ...

math - the points (-9,0) and (19,0) lie on parabola. a.) determine an equation ...

Algebra - I am given a graph of a parabola and I have to write a function in at ...

conics - The graph of y=x^2 is reflected in the x-axis, then stretched ...

Pre-Calculus - I am having trouble with several problems: 1) Find the ...

Pre-Calculus - I am having trouble with several problems: 1) Find the ...

algebra help please - I notice that other problems are answered in a timely ...