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July 28, 2014

July 28, 2014

Posted by **Soly** on Saturday, October 13, 2007 at 11:43pm.

Find the coordinates of the vertex for the parabola defined by the given quadratic function.

1.f(x) = (x - 4)2 - 4

Find the axis of symmetry of the parabola defined by the given quadratic function.

3.f(x) = (x + 2)2 + 7

Find the range of the quadratic function.

5.f(x) = 7 - (x + 4)2

- Algebra -
**Reiny**, Sunday, October 14, 2007 at 1:25amfor any parabola of the form

f(x) = a(x-h)^2 + k

the vertex is (h,k) and the axis of symmetry is x = h

Make use of that fact for #1 and #3

The range is the set of y values that the graph covers.

so in #5 first rewrite it as

f(x) = -(x+4)^2 - 7

Wouldn't the vertex be (-4,-7) and since the parabola opens downwards, what do you thing would be the y values covered by the graph?

- Algebra -
**Soly**, Sunday, October 14, 2007 at 11:03pmPlease check my answers.

Find the coordinates of the vertex for the parabola defined by the given quadratic function.

1.f(x) = (x - 4)2 - 4

-I got (4,-4)

Find the axis of symmetry of the parabola defined by the given quadratic function.

3.f(x) = (x + 2)2 + 7

-I got: x=-2

Find the range of the quadratic function.

5.f(x) = 7 - (x + 4)2

I got: (-inifinity,7]

- Algebra -
**kayla**, Tuesday, April 20, 2010 at 11:39pmfind the coordinates of the vertex for the parabola defined by the given quadratic function f(x)=(x+7)^2-6

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