Posted by Jack on Saturday, October 13, 2007 at 4:49pm.
When the car is over the top of the bump it is accelerating downward. The acceleration is
a = v^2/r = (13 m/s)^2/(33.2 m)
= 5.09 m/s^2
72.7 kg person is thus accelerated downward at this acceleration.
Newton's second law says that:
F = m a
Let'S apply this to the person. There are two forces that act on the person. There is the gravitational force exerted by the entire Earth on the person. This force is directed downward and has a magnitude of:
F_g = 72.7 kg * g = 713 N
And there is the foce exerted by the chair F_ch
If the take the downward direction to be positive, we have:
(F_g + F_ch) = 72.7 kg * 5.09 m/s^2 --->
F_ch = -343 N
The minus sign means that it is directed upward.
Related Questions
Physics - Driving in your car with a constant speed of 12 m s you encounter a ...
physics - Driving in your car with a constant speed of 12 m/s, you encounter a ...
Physics - Driving in your car with a constant speed of 12 , you encounter a bump...
physics - Driving in your car with a constant speed of 12 m/s, you encounter a ...
physics - driving in a car with constant speed of 12m/s,then encounter to a bump...
PHYSICS - Driving in your car with a constant speed of v = 11.7 m/s, you ...
Physics - An 893 kg car passes over a bump in a road that follows the arc of a ...
Physics - A stuntman drives a car over the top of a hill, the cross section of ...
physics - Two cars are traveling at the same constant speed v. Car A is moving ...
physics - Which situations are examples of a particle with a non-zero ...
For Further Reading