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January 31, 2015

January 31, 2015

Posted by **Soly** on Friday, October 12, 2007 at 10:45pm.

Find an nth degree polynomial function with real coefficients satisfying the given conditions.

1. n=3; 3 and i are zeros; f(2)=20

-I got: f(x)=-4^3+12x^2-4x+12

3.n=3;4 and i zeros;f(-3)=60

-I got:f(x)=6x^3+24x^2+6x+24

- Algebra -
**Reiny**, Friday, October 12, 2007 at 11:05pmthe first one is correct, the 2nd is not

try f(4) in your equation, you do not get zero.

I had f(x) = a(x^2+1)(x-4)

then for f(-3)=60

60 = a(10)(-7)

a= -6/7

so f(x) = -6/7(x^2+1)(x-4)

expand it for your answer

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