Posted by Hunter on .
Am completely stuck on this one, so am having a hard time explaining the stepbystep instructions for solving the problem below. Help would be greatly appreciated.
Two travelers are 220 kilometers apart at noon and are headed toward each other along a straight road. They meet at 5:30 PM, and one traveled 20 kilometers per hour faster than the other. What is the speed of the faster traveler?

Math  Algebra 
bobpursley,
When did they leave? One has to have time, or velocity given.

Math  Algebra 
Hunter,
The problem only indicates that they are 220 kilometers apart at noon.

Math  Algebra 
Reiny,
Each traveled 5.5 hours
I made a chart
..........Distance....rate........time
trav#1......5.5x......x km/h.....5.5 hrs
trav#2....5.5(x+20)...x+20 km/h..5.5 hrs
...total...220
so 5.5x + 5.5(x+20) = 220
solve, it is easy from here on.
(I got 30 km/h) 
Math  Algebra 
Hunter,
Thank you very much!

Math  Algebra 
tchrwill,
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Homework Help Forum: Math  Algebra
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Posted by Hunter on Friday, October 12, 2007 at 9:55pm.
Am completely stuck on this one, so am having a hard time explaining the stepbystep instructions for solving the problem below. Help would be greatly appreciated.
Two travelers are 220 kilometers apart at noon and are headed toward each other along a straight road. They meet at 5:30 PM, and one traveled 20 kilometers per hour faster than the other. What is the speed of the faster traveler?
They are 220km apart and approaching one another at the combined speed of V + (V + 20) = 2V + 20.
Therefore,from V = D/T, 220 /(2V + 20) = 5.5 which leads to 220 = 11V += 110 fromw which 11V = 110 and V = 10 making the faser speed 30 km/hr.