When did they leave? One has to have time, or velocity given.
The problem only indicates that they are 220 kilometers apart at noon.
Each traveled 5.5 hours
I made a chart
trav#1......5.5x......x km/h.....5.5 hrs
trav#2....5.5(x+20)...x+20 km/h..5.5 hrs
so 5.5x + 5.5(x+20) = 220
solve, it is easy from here on.
(I got 30 km/h)
Thank you very much!
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Posted by Hunter on Friday, October 12, 2007 at 9:55pm.
Am completely stuck on this one, so am having a hard time explaining the step-by-step instructions for solving the problem below. Help would be greatly appreciated.
Two travelers are 220 kilometers apart at noon and are headed toward each other along a straight road. They meet at 5:30 PM, and one traveled 20 kilometers per hour faster than the other. What is the speed of the faster traveler?
They are 220km apart and approaching one another at the combined speed of V + (V + 20) = 2V + 20.
Therefore,from V = D/T, 220 /(2V + 20) = 5.5 which leads to 220 = 11V += 110 fromw which 11V = 110 and V = 10 making the faser speed 30 km/hr.