Posted by **Mary** on Friday, October 12, 2007 at 7:28pm.

I didn't help with my last math problem:

Perform the indicated operations.

14x-7/x^2+3x-4 * x^2+6x+8/2x^2+5x-3 / x^2+2x/x^2+2x-3

I appreciate the help.

- algebra -
**Reiny**, Friday, October 12, 2007 at 7:41pm
I will assume you meant the following:

(14x-7)/(x^2+3x-4) * (x^2+6x+8)/(2x^2+5x-3) รท (x^2+2x)/(x^2+2x-3)

Then everything factors very nicely and my answer was 7/x

Don't forget the restrictions of

x not= -4,1,-3,1/2,-2,0

Hint:(my restrictions should give you a clue what the factors of the denominators were)

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