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March 26, 2017

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find the area of a circle inscribed in triangle ABC where a=9, b=13, and the measure of angle C=38 degrees

  • Pre Calculus/Trig - ,

    You can get c with the law of cosines.

    Then, draw the figure. You have a multitude of similar triangles. The idea is to use them to find the measure of radius, the distance on many of those triangles.

  • Pre Calculus/Trig - ,

    I've tried that multiple times, but I was told the answer should be more than one. I get something around .07

  • Pre Calculus/Trig - ,

    As suggested by bobpursley, use the cosine law to get c, I got 8.1

    Now use the Sine Law to find angle A, which I got to be 43.16º

    Let P be the centre of the incsribed triangle. A property of that circle is that its centre is the intersection of the angle bisectors of the triangle.

    Consider triangle APC. Angle C is 19º, AC = 13 and angle A is 21.58º

    (If you have a triangle with its base known and the two angles on that base A and C are known, then the height is given by
    Height = base/(cot A + cot C)

    in this case
    height = 13/(cot19º + cot21.58º)
    = 2.393
    This is the radius of your circle, so the area is pi(2.393)^2
    = 17.99 or 18 units

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