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March 27, 2017

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Use the definition of the derivative to find f'(x)

1. f(x) 2x^2 + x - 1

Before the final step, my 'result' looked weird and I think I did something wrong in my arithmetic...someone correct me?

Here's my work...

BEGINNING STEP:
lim [2(x + deltaX)^2 - (x + deltaX) - (2x^2 + x - 1)] / deltaX

near the end step:
lim [4x + 2deltaX - 2x^2 - 1] / deltaX

Thanks

  • Calculus - need help! - ,

    You started correctly, but you must have a math error in the intermediate steps.

    ((2(x+deltaX)^2 + (x+deltaX) - 1) - (2x^2 + x - 1) )/deltaX
    =((2x2+4(x*deltaX) + 2deltaX^2 + x + deltaX - 1) - (2x^2 + x - 1) ) /deltaX
    =(4(x*deltaX) + 2*deltaX^2 + deltaX)/deltaX
    =4x + deltaX + 1
    limit as delatX goes to 0
    =4x + 1

  • Calculus - need help! - ,

    Ooops!
    the step before the limit statement should have read:
    4x + 2deltaX + 1

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