it says find the x intercept of the quadratic equation;
2x^2+3x+4=0
To find the x-intercept of the quadratic equation 2x^2 + 3x + 4 = 0, we need to find the values of x for which the equation is equal to zero. In other words, we need to solve the equation.
One way to do this is by factoring the quadratic equation. However, this particular equation cannot be factored easily, so we will use the quadratic formula.
The quadratic formula is:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our equation, a = 2, b = 3, and c = 4. Plugging these values into the quadratic formula, we get:
x = (-3 ± √(3^2 - 4*2*4)) / (2*2)
Simplifying further, we have:
x = (-3 ± √(9 - 32)) / 4
= (-3 ± √(-23)) / 4
Since we have a negative value under the square root, the quadratic equation has no real solutions. This means there are no x-intercepts in this case.
The graph of the quadratic equation 2x^2 + 3x + 4 = 0 will not intersect the x-axis.