you lift a 10 N physics book up in the air a distance of 1m at a constant velocity of .5m/s. What is the work done by the weight of the book?

Question

you lift a 10 N physics book up in the air a distance of 1m at a constant velocity of .5m/s. What is the work done by the weight of the book?

a) +10 J
b)-10 J
c) +5 J
d)-5 J

10 N is the force of gravity and to find work you do this: W=F_g(change in distance)
(10N)(1m)= +10J so the correct answer is a). Is this correct?

Answer 1

You are doing work on gravity, so it will be negative work done by the book (the book gains energy)

work= weight(height)
-10 J is the work done by gravity.

Answer 2

Yes, your reasoning is correct. The work done by the weight of the book can be calculated using the formula W = F * d, where W is the work done, F is the force, and d is the displacement. In this case, the force is 10 N (the weight of the book) and the displacement is 1 m. Plugging these values into the formula, we get W = 10 N * 1 m = +10 J. Therefore, the correct answer is a) +10 J.

Answer 3

Yes, your understanding and calculation are correct. To find the work done by the weight of the book, you multiply the force of gravity (10 N) by the change in distance (1 m). Since the book is lifted at a constant velocity, the work done is equal to the force multiplied by the distance. Therefore, the work done by the weight of the book is 10 J (positive because the force and displacement are in the same direction). So, the correct answer is option a) +10 J.

Answer 4

you lift a 10 N physics book up in the air a distance of 1m at a constant velocity of .5m/s. What is the work done by the weight of the book?

You are doing work on gravity, so it will be negative work done by the book (the book gains energy)

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