posted by Tammy on .
you lift a 10 N physics book up in the air a distance of 1m at a constant velocity of .5m/s. What is the work done by the weight of the book?
a) +10 J
c) +5 J
10 N is the force of gravity and to find work you do this: W=F_g(change in distance)
(10N)(1m)= +10J so the correct answer is a). Is this correct?
You are doing work on gravity, so it will be negative work done by the book (the book gains energy)
-10 J is the work done by gravity.