posted by Tammy on .
A wooden block slides directly down an incline plane at a constant velocity of 6 m/s. What is the coefficient of kinetic friction if the plane makes an angle of 30 degrees with the horizontal?
the coefficient of kinetic friction = force of kinetic friction/normal force. How would i solve this problem? i am only given velocity and the angle. I can't figure out the equation for this problem. Thanks in advance for your help.
The downward force along the plane is mg*sin30. If the block is at constant velocity, then this must equal friction force.Friction force is mu*mg*cos30
mu= tan 30
An object of mass 20kg slides down an inclined plane at an angle of 30degrees to the horizontal. The coefficient of static friction is what?