Tuesday

September 16, 2014

September 16, 2014

Posted by **Ash** on Tuesday, October 9, 2007 at 9:33pm.

Here are my questions:

Use Decartes Rule of signs to determine the possible number of postive and negative real zeros for the given function.

1. f(x)=-7x^9+x^5-x^2+6

choices are:

a. 2 or 0 positive zeros,2 or 0 negative zeros

b.2 or 0 positive zeros, 3 or 1 negative zeros

c.3 or 1 positive zeros, 3 or 1 negative zeros

d. 3 or 1 positive zeros, 2 or 0 negative zeros

2. f(x)10x^3-8x^2+x+5

my choices are:

a. 3 or 1 positive zeros, 1 negative zero

b.2 or 0 positive zeros, no negative zeros

c.3 or 1 positive zeros, 2 or 0 negative zeros

d.2 or 0 positive zeros, 1 negative zero

- Decartes Rule of Signs -
**bobpursley**, Tuesday, October 9, 2007 at 9:41pmI will be happy to check your answers or thinking.

http://www.purplemath.com/modules/drofsign.htm

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