assuming that the calorimeter contains 5.00 * 100 g of water and that the initial temperature is 30.0 degree celcius. what will the final temperature be? (use the proper formula and units, and show your work below)

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I'd love to know myself, chem is so stupid and a waste of time am I right?

To calculate the final temperature of the water in the calorimeter, we need to use the formula for heat transfer:

Heat gained by the water = Heat lost by the calorimeter

The formula for heat transfer is:

Q = mcΔT

Where:
Q is the heat gained or lost
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature

In this case, we assume that the calorimeter loses heat and the water gains heat. The specific heat capacity of water is 4.18 J/(g·°C). Considering that the calorimeter loses heat, we assume that the change in temperature for the water is positive and for the calorimeter is negative.

Let's calculate the heat lost by the calorimeter first. Since the calorimeter doesn't change its temperature, ΔT_calorimeter = final temperature - initial temperature.

Now we can calculate the heat gained by the water. The initial temperature of the water is 30.0 °C, and we assume it changes to the final temperature.

The equation becomes:

Q_water = mc_waterΔT_water
Q_calorimeter = mc_calorimeterΔT_calorimeter

Since the heat lost by the calorimeter is equal to the heat gained by the water:

mc_waterΔT_water = mc_calorimeterΔT_calorimeter

Since we have the mass and initial temperature of the water, we can rearrange the equation to solve for the final temperature (ΔT_water):

ΔT_water = (mc_calorimeterΔT_calorimeter)/(mc_water)

Now, let's substitute the given values into the equation and solve for the final temperature:

m_water = 5.00 * 100 g (mass of water)
c_water = 4.18 J/(g·°C) (specific heat capacity of water)
ΔT_calorimeter = final temperature - 30.0 °C

Final Temperature Calculation:

ΔT_water = (mc_calorimeterΔT_calorimeter) / (mc_water)
ΔT_water = (100 g * c_calorimeter * (final temperature - 30.0 °C)) / (5.00 * 100 g * c_water)

Cancelling out the masses:

ΔT_water = (c_calorimeter * (final temperature - 30.0 °C)) / c_water

Now, we can rearrange the equation further:

ΔT_water * c_water = c_calorimeter * (final temperature - 30.0 °C)

Finally, solving for the final temperature:

(final temperature - 30.0 °C) = (ΔT_water * c_water) / c_calorimeter
final temperature = (ΔT_water * c_water) / c_calorimeter + 30.0 °C

Remember to substitute the values of ΔT_water, c_water, and c_calorimeter into the equation to find the final temperature.