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chemistry

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At 1100 K, Kp = 0.25 for the reaction
2SO2(g) + O2(g) equilibrium with 2SO3(g)
What is the value of Kc at this temperature?

  • chemistry - ,

    Kc = Kp-delta n

  • chemistry - ,

    is .25 the right answer? if Kp = to .25 and -delta n is the # of mols in prod - # of mols in reactants then that equals out to 1. please tell me if i messed up somewhere

  • chemistry - ,

    No. You haven't multiplied by RT but I goofed and didn't put that in my answer.
    Kc = Kp(RT)-delta n
    Kc = 0.25[0.08205*1100)-(-1)
    You are right that delta n is 2-3 = -1

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