Post a New Question

Algebra I

posted by .

1. A Passenger train's speed is 60mi/h and a freight train's speed is 40mi/h. The passenger train travels the same distance in 1.5 h less time than the freight train. How long does each train take to make the trip?

2. Lois rode her bike to visit a friend. She traveled at 10 mi/h. While she was there it began to rain. Her friend drove her home in a car traveling at 20 mi/h. Lois took 1.5 h longer to go to her friend's than to return home. How many hours did it take Lois to ride to her friend's house?

  • Algebra I -

    distance = rate x time
    passenger train rate = 60 mi/hr
    freight train rate = 40 mi/hr.
    distance traveled by P = 60*t
    distance traveled by F = 40*t
    time for F is 1.5 hours longer than P so
    F dist = 40(t+1.5) = P dist = 60*t
    set distance = to each other
    60*t=40(t+1.5)
    solve for t = time for passenger train.
    Then t+1.5 = tiome for freight train.

  • Algebra I -

    #2 is done the same say as #1. Post your work if you get stuck.

  • Algebra I -

    2:30

  • Algebra I -

    40(t+1.5)=60x t

    2/3(t+1.5)= T

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question