Posted by **Wilford** on Tuesday, October 9, 2007 at 8:19pm.

1. A Passenger train's speed is 60mi/h and a freight train's speed is 40mi/h. The passenger train travels the same distance in 1.5 h less time than the freight train. How long does each train take to make the trip?

2. Lois rode her bike to visit a friend. She traveled at 10 mi/h. While she was there it began to rain. Her friend drove her home in a car traveling at 20 mi/h. Lois took 1.5 h longer to go to her friend's than to return home. How many hours did it take Lois to ride to her friend's house?

- Algebra I -
**DrBob222**, Tuesday, October 9, 2007 at 8:35pm
distance = rate x time

passenger train rate = 60 mi/hr

freight train rate = 40 mi/hr.

distance traveled by P = 60*t

distance traveled by F = 40*t

time for F is 1.5 hours longer than P so

F dist = 40(t+1.5) = P dist = 60*t

set distance = to each other

60*t=40(t+1.5)

solve for t = time for passenger train.

Then t+1.5 = tiome for freight train.

- Algebra I -
**DrBob222**, Tuesday, October 9, 2007 at 8:39pm
#2 is done the same say as #1. Post your work if you get stuck.

- Algebra I -
**Dalia**, Monday, November 10, 2008 at 10:10pm
2:30

- Algebra I -
**Riley**, Monday, September 27, 2010 at 8:05pm
40(t+1.5)=60x t

2/3(t+1.5)= T

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