SUPPOSE THAT THE ELECTRIC POTENTIAL OUTSIDE A LIVING CELL IS HIGHER THAN THAT INSIDE THE THE CELL BY .068 V. HOW MUCH WORK IS DONE BY THE ELECTRIC FORCE WHEN A SODIUM ION (CHARGE = e+) MOVES FROM THE OUTSIDE TO THE INSIDE?

ANSWER = ? J

work= charge*voltage

To calculate the work done by the electric force when a sodium ion moves from the outside to the inside of a living cell, we need to use the formula:

Work (W) = Charge (q) x Change in electric potential (ΔV)

Given:
Charge of sodium ion (q) = +1 unit of elementary charge (e+)
Change in electric potential (ΔV) = 0.068 V (the potential difference between inside and outside the cell)

We can substitute the values into the formula:

W = (q) x (ΔV)
W = (+1 e+) x (0.068 V)

Now, we need to convert the charge from elementary charge (e+) to Coulombs (C) to match the units with voltage:

1 e+ = 1.602 x 10^-19 C (approximation)

W = (1.602 x 10^-19 C) x (0.068 V)

Now we can calculate the value of W:

W = 1.08976 x 10^-20 J

Therefore, the work done by the electric force when a sodium ion moves from the outside to the inside of the cell is approximately 1.08976 x 10^-20 Joules (J).