Posted by Mary on Tuesday, October 9, 2007 at 6:32pm.
The change in B divided by the time (0.45 s), multiplied by the loop area in square meters, is the average voltage in the loop during the interval. The wire resistance is 2 pi R * 3.3 10-2 ohms(?)/m.
Coumpute the average current (Vav/R) and multiply it by the average voltage, Vav, computed by the method above.
Average Power =
[(delta B)(pi R^2)/(delta t)]^2/(2 pi R)
= (1/2) pi* R^3 [(delta B)/(delta t)]^2
Check my math and my logic. I could be wrong
A thin tube stretch across a street counts the number of pairs of wheels that pass over it. A vehicle classified as Type A with two axles registers two counts. A vehicle classified as Type B with three axles registers three counts. During a 1 hour period a traffic counter registered 35 counts. How many type A vehicles and type b vehicles passed over the traffic?
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