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March 28, 2017

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The combustion of carbon monoxide is represented by the equation below:

CO (g) + 1/2O2 (g) ----> CO2 (g)

a) determine the value of the standard enthalpy change, for the combustion of CO at 298 K using the following info.

C (s) + 1/2 O2(g) ----> CO (g)
delta H at 298K = -110.5 kJ/mol

C(s) + O2 (g) ----> CO2
delta H = -393.5 kJ/mol

so far i have:
1/2 C (s) + 1/4 O2 (g) ----> 1/2 CO

and C (s) + O2 (g) ----> Co2

I'm kind confused as to what i'm supposed to do and how i'm supposed to use the info. am i on the right track? if not, could you tell me how it works? thanks

  • Chemistry - ,

    let A= CO2
    B= CO


    elements> A gives 393kj/mol heat
    elements>B gives 110kj/mol
    Question is B > A

    elements >
    B > A
    You know elements >A
    and elements > B, so
    B>A must be the difference
    -393 - (-110)= ...

  • Chemistry - ,

    Yes you are on the right track but you just need a little redirection.
    Reverse C + 1/2O2 ==> CO and change sign of delta H.
    Add C+O2 ==> CO2 and keep delta H as is.
    Now add the two equations and see if you get CO + 1/2 O2 ==> CO2. Add delta Hs.
    Thanks for posting your work.

  • Chemistry - ,

    Thanks for your help!

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