It takes 2.5 s for a small ball released from rest from a tall building to reach the ground. The mass of the ball is 0.05 kg. Calculate the height from which the ball is released.

Ok so I have the time, initial velocity, and the acceleration. But the mass totally throws me off...what would the formula for this problem be?

Never mind! The mass has nothing do with the problem. I got it. :)

To solve this problem, we can use the formula for the height of an object in free fall:

h = (1/2) * g * t^2

Where:
h is the height from which the object is released,
g is the acceleration due to gravity (approximately 9.8 m/s^2),
and t is the time it takes for the object to reach the ground.

However, the given information includes the mass of the ball, which is not necessary to find the height in this case. The mass does not affect the time it takes for the ball to fall.

So, the formula to calculate the height from which the ball is released is simply:

h = (1/2) * g * t^2

Plugging in the values:
t = 2.5 s
g = 9.8 m/s^2

h = (1/2) * 9.8 m/s^2 * (2.5 s)^2
h = (1/2) * 9.8 m/s^2 * 6.25 s^2
h = 3.125 m^2/s^2 * 9.8 m/s^2
h = 30.625 m

Therefore, the height from which the ball is released is approximately 30.625 meters.

To solve this problem, you can use the equations of motion for constant acceleration. The relevant equation in this case is:

h = (1/2)gt^2

Where:
h = height from which the ball is released
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time taken for the ball to fall (2.5 s)

However, the equation above does not involve the mass of the ball, so you do not need to consider it to solve this particular problem. The mass of the ball would only be necessary if you wanted to calculate the force acting on the ball (which is not required here).

Substituting the given values into the equation:

h = (1/2)(9.8 m/s^2)(2.5 s)^2

Now, you can calculate the height by plugging in the values and performing the necessary calculations:

h = (1/2)(9.8 m/s^2)(6.25 s^2)
h = (4.9 m/s^2)(6.25 s^2)
h = 30.625 m^2/s^2

Therefore, the height from which the ball is released is approximately 30.625 meters.