I have few questions that I need checked please and could you help me with the last question?

Write an equation that expreses the relationship. Use k as the constant of varaiation.

1. s varies directly as h
-I got: s=kh

2.a varies directly as the square of m.
-I got: a=km^2

Determine the constant of variation the stated condition.

6. b varies directly as a, and b=90 when a=6.
-this is what I did: 90=k/6, then I multiplied each side by 6, (6)(90)=k(6)/(6)(6), I got k=15.

If y varies directly as x, find the direct variation equation for the situation.
10. y=4 when x=20
-This question I don't understand

all right so far,

10) y=kx
k= y/x= 4/20
y= (4/20) x

Write the equation of direct variation for x = -5 and y = 90.

hei soly,

mey nime is tom atos. i berelive tat des qerstetion es werong! whay u arsk? bevaues dat ern broblem in ern meddle is wierd.

herve fern!

tom atos <333

To find the direct variation equation when y varies directly as x, we need to determine the constant of variation. In direct variation, the constant of variation is the ratio between the two variables.

In the given situation, we have y = 4 when x = 20. To find the constant of variation, we can use the formula:

k = y/x

Substituting the values, k = 4/20 = 0.2.

Therefore, the direct variation equation for this situation is:

y = 0.2x

This equation represents the relationship between y and x when y varies directly as x.