Physics
posted by ac on .
A track star in the long jump goes into the jump at 12 m/s and launches herself at 20 degrees above the horizontal. How long is she in the air before returning to Earth? (g= 9.81 m/s squared)
I tried using some formulas but I'm using all of the wrong formulas for this question. I can work this out if someone can give me the correct formula to use. :)
Thanks!

You know the intial height, and the final height. You know the initial velocity.
hfinal=hinitial + v*sin20*t 1/2 g t^2
solve for t. 
Thanks! ^^

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