February 24, 2017

Homework Help: Physics

Posted by Student on Sunday, October 7, 2007 at 1:43pm.

A stone has a mass of 3.0 10-3 kg and is wedged into the tread of an automobile tire, as the drawing shows. The coefficient of static friction between the stone and each side of the tread channel is 0.86. When the tire surface is rotating at 10 m/s, the stone flies out of the tread. The magnitude FN of the normal force that each side of the tread channel exerts on the stone is 1.8 N. Assume that only static friction supplies the centripetal force, and determine the radius r of the tire.

well so far i THINK that since the rock is stuck between a wedge, the Fn would be 3.6, and since Fs = .86(3.6) = 3.096. And I see that since Fc = (mv^2)/ r, and this would mean that r = (mv^2) / Fc. The mass is .003 kg, and v = 10m/s.. Im having trouble finding Fc

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions